and changed to TQ with muffler off etc LOL.Its the fact that Engine manufacturers were advertising power ratings achieved without a muffler, without an air filter, at engine speeds that exceeded the governed top speed of the engine.
FOr instance...a 31ci single cylinder engine, at 4100 might make 21hp, but at 3600 it makes 18hp, so they advertise the 21hp, but it was limited to 18hp, ad an air filter, muffler, intake tract...16.5hp or less...but still advertised @ 21hp.
If the formula is just that simple, How is it that though two engines have the same torque at the same RPM, one of them is discribed as "torquey"?HP can only be calculated mathmatically. TQ is the number that is found on a dyno, and HP is calculated from that. I believe the formula for calculating HP is: TQ x RPM divided by 5252. I could be wrong, but that's how I remember it.
And now they will do the same thing with torque. Then, they will be limited to only using c.i. discriptions.Its the fact that Engine manufacturers were advertising power ratings achieved without a muffler, without an air filter, at engine speeds that exceeded the governed top speed of the engine.
No worms on this board!For example, If you are towing something heavy you probably want higher torque values at low rpm's
Then if the formula is valid, you have higher HP at lower RPM.
Prop the boat so that the engine hits peak HP rpm's at wide open throttle and you are there. There is likely higher peak torque at lower rpm's. It is not going to make the boat faster to prop it for peak rpm's to match peak torque.
??? So at higher RPMs the torque goes down, but the RPMs go up, so how does this affect the formula? I understand what torque is and I understand what HP is, I just have trouble understanding how they are interconnected by a formula.
I've seen Torque vs HP debates go south on other boards so I hope I'm not opening up a can of worms here.
That example is not a real world application, just an alliterative device to illustrate that torque is where it's at if you want to pull a load slowly, and HP is where it's at if you want to go fast. It's a generalization and can easily be picked apart.SO! Still confused! In the horse/elephant example, which has more horse power, (or elephant power), the horse or the elephant?
-----they make have same torque at one particular rpm only. I would think an engine whose torque is higher than the other at low rpms would be considered torqueree .Generally on any engine the torque increases with rpm but gradually increases less and less until it peaks and then drops for further increase in RPM . that is called the torque curve-------If the formula is just that simple, How is it that though two engines have the same torque at the same RPM, one of them is discribed as "torquey"?
And now they will do the same thing with torque. Then, they will be limited to only using c.i. discriptions.
I think I see now. Good example.Think of it this way. If torque stays the exact same fro say 4000-5000 rpms. HP will go up because HP = torque * RPM's / constant number. so in this case as RPM's increase so does HP.
Now if there is a slight loss of torque as rpm's increase then depending on the rate of torque loss HP can increase. This is exactly what happens. as Torque goes past it's peak the rate of loss is gradually increasing (slope for engineering types). There will be a region where torque is decreasing and HP is increasing immediately following peak torque rpm's
Look at any dyno sheet (google dyno). I'll bet that peak HP will always be at higher rpm's than peak torque.